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Question

Suppose P(A)=40%P\left(A\right)=40\%, P(Aˉ)=60%P\left(\bar{A}\right)=60\%, P(B∣A)=70%P\left(B\mid A\right)=70\%, and P(B∣Aˉ)=20%P\left(B\mid\bar{A}\right)=20\%. Find P(A∣B)P\left(A\mid B\right) using Bayes' Theorem.

Accepted Answer

70%70\%

Answer

12%12\%

Answer

28%28\%

Answer

40%40\%

Suppose P(A)=40%P\(\left\)(A\(\right\))=40\%, P(Aˉ)=60%P\(\left\)(\(\bar{A}\]\right\))=60\%, P(B∣A)=70%P\(\left\)(B\(\mid\) A\(\right\))=70\%, and P(B∣Aˉ)=20%P\(\left\)(B\(\mid\[\bar{A}\]\right\))=20\%. Find P(A∣B)P\(\left\)(A\(\mid\) B\(\right\)) using Bayes' Theorem.

Suppose $P of A equals 40 percent sign$ , $P of open paren A ˉ close paren equals 60 percent sign$ , $P of open paren B divides A close paren equals 70 percent sign$ , and $P of open paren B divides A ˉ close paren equals 20 percent sign$ . Find $P (A ∣ B)$ using Bayes' Theorem.