Solve the differential equation using variation of parameters: . Which of the following is the general solution?
Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
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- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
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- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 34m
- 12. Techniques of Integration7h 39m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
13. Intro to Differential Equations
Basics of Differential Equations
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Solve the differential equation using variation of parameters: . Which of the following is the general solution?
A
B
C
D

1
Step 1: Identify the type of differential equation. The given equation is a second-order linear non-homogeneous differential equation: y'' + 3y' + 2y = 1/3 + e^x.
Step 2: Solve the corresponding homogeneous equation y'' + 3y' + 2y = 0. Find the characteristic equation: r^2 + 3r + 2 = 0. Factorize it to find the roots r = -1 and r = -2. The general solution of the homogeneous equation is y_h = C_1 e^{-x} + C_2 e^{-2x}.
Step 3: Use the method of variation of parameters to find a particular solution y_p for the non-homogeneous equation. The method involves finding two functions u_1(x) and u_2(x) such that y_p = u_1(x)y_1 + u_2(x)y_2, where y_1 = e^{-x} and y_2 = e^{-2x} are solutions of the homogeneous equation.
Step 4: Compute u_1(x) and u_2(x) using the formulas derived from variation of parameters. These formulas involve integrating expressions that include the Wronskian of y_1 and y_2, as well as the non-homogeneous term (1/3 + e^x). After integration, determine the particular solution y_p.
Step 5: Combine the homogeneous solution y_h and the particular solution y_p to form the general solution: y = y_h + y_p = C_1 e^{-x} + C_2 e^{-2x} + 1/6 + (1/2)x e^x.
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