Find the general solution of the system of differential equations:
Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 34m
- 12. Techniques of Integration7h 39m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
13. Intro to Differential Equations
Basics of Differential Equations
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Solve the differential equation using variation of parameters: . Which of the following is the general solution?
A
B
C
D

1
Step 1: Identify the type of differential equation. The given equation is a second-order linear non-homogeneous differential equation: . The solution will consist of the complementary solution (solution to the homogeneous equation) and a particular solution (solution to the non-homogeneous part).
Step 2: Solve the homogeneous equation. The homogeneous equation is . Solve this by finding the characteristic equation: . Factorize the characteristic equation to find the roots, which will determine the complementary solution.
Step 3: Write the complementary solution. Based on the roots of the characteristic equation, the complementary solution will be of the form , where and are constants.
Step 4: Find the particular solution using variation of parameters. For the non-homogeneous term , assume a particular solution of the form . Substitute into the original equation and solve for and by equating coefficients.
Step 5: Combine the complementary and particular solutions. The general solution to the differential equation is , which combines the complementary solution and the particular solution obtained in Step 4.
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