Which of the following integrals represents the area of the region bounded by the curves and between and ?
Table of contents
- 0. Functions7h 55m
- Introduction to Functions18m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms36m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 31m
- 12. Techniques of Integration7h 41m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
8. Definite Integrals
Introduction to Definite Integrals
Multiple Choice
What is the average (mean) value of the function over the interval ?
A
B
C
D
0 Comments
Verified step by step guidance1
Step 1: Recall the formula for the average value of a function f(t) over an interval [a, b]: \( \text{Average Value} = \frac{1}{b-a} \int_{a}^{b} f(t) \, dt \). Here, \( f(t) = 3t^3 - t^2 \), \( a = 1 \), and \( b = 2 \).
Step 2: Set up the integral \( \int_{1}^{2} (3t^3 - t^2) \, dt \). This involves finding the antiderivative of \( 3t^3 - t^2 \).
Step 3: Compute the antiderivative of \( 3t^3 - t^2 \). The antiderivative of \( 3t^3 \) is \( \frac{3t^4}{4} \), and the antiderivative of \( -t^2 \) is \( -\frac{t^3}{3} \). Combine these to get \( \frac{3t^4}{4} - \frac{t^3}{3} \).
Step 4: Evaluate the definite integral \( \int_{1}^{2} (3t^3 - t^2) \, dt \) by substituting the limits of integration into the antiderivative. This means calculating \( \left[ \frac{3t^4}{4} - \frac{t^3}{3} \right]_{1}^{2} \), which involves substituting \( t = 2 \) and \( t = 1 \) and subtracting.
Step 5: Divide the result of the definite integral by \( b-a \), which is \( 2-1 = 1 \), to find the average value of the function over the interval. The final average value is \( \frac{1}{1} \int_{1}^{2} (3t^3 - t^2) \, dt \).
Related Videos
Related Practice
Multiple Choice
116
views

