Find the general solution of the differential equation .
Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 34m
- 12. Techniques of Integration7h 39m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
13. Intro to Differential Equations
Basics of Differential Equations
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Find the general solution of the differential equation .
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Step 1: Start by analyzing the given differential equation y^{(4)} + y''' + y'' = 0. This is a linear homogeneous differential equation with constant coefficients.
Step 2: Assume a solution of the form y(x) = e^{rx}, where r is a constant. Substitute y(x) = e^{rx} into the differential equation to obtain the characteristic equation.
Step 3: The characteristic equation is derived by substituting y(x) = e^{rx} into the differential equation, resulting in r^4 + r^3 + r^2 = 0. Factorize this equation to find the roots.
Step 4: Factorize r^4 + r^3 + r^2 = 0 as r^2(r^2 + r + 1) = 0. This gives two types of roots: r = 0 (with multiplicity 2) and the roots of r^2 + r + 1 = 0, which are complex roots.
Step 5: Solve r^2 + r + 1 = 0 using the quadratic formula r = (-b ± √(b^2 - 4ac)) / 2a. Here, a = 1, b = 1, and c = 1. The roots are complex numbers, and the general solution is formed by combining the real and complex roots into the form y(x) = C_1 + C_2 x + C_3 e^{r_1 x} + C_4 e^{r_2 x}, where r_1 and r_2 are the complex roots.
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