Solve the differential equation using variation of parameters: . Which of the following is the general solution?
Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 34m
- 12. Techniques of Integration7h 39m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
13. Intro to Differential Equations
Basics of Differential Equations
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Suppose that solves the ordinary differential equation with the initial condition . What is ?
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Step 1: Recognize that the given differential equation is a first-order linear ordinary differential equation of the form y' = ky, where k = 3 in this case. This type of equation has a standard solution form y(x) = Ce^(kx), where C is a constant determined by the initial condition.
Step 2: Substitute the given initial condition y(0) = 2 into the general solution y(x) = Ce^(kx). This will allow us to solve for the constant C.
Step 3: Evaluate y(0) = Ce^(3*0). Since e^(0) = 1, this simplifies to y(0) = C. Using the initial condition y(0) = 2, we find that C = 2.
Step 4: Substitute the value of C back into the general solution y(x) = Ce^(kx). This gives y(x) = 2e^(3x).
Step 5: Verify the solution by differentiating y(x) = 2e^(3x) to check that it satisfies the original differential equation y' = 3y. Differentiating, we find y'(x) = 6e^(3x), and substituting y(x) = 2e^(3x) into y' = 3y confirms that the equation holds true.
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