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Multiple Choice
Which of the following functions is continuous on the interval ?
A
B
C
D
Verified step by step guidance
1
Step 1: Understand the concept of continuity. A function is continuous on an interval if it is defined and does not have any breaks, jumps, or asymptotes within that interval.
Step 2: Analyze the function f(x) = 1/x. This function is undefined at x = 0, which is within the interval (0, 1). Therefore, it is not continuous on (0, 1).
Step 3: Analyze the function f(x) = ln(x). The natural logarithm function is defined only for x > 0, and it is continuous for all positive values of x. Since the interval (0, 1) lies entirely within the domain of ln(x), this function is continuous on (0, 1).
Step 4: Analyze the function f(x) = sqrt(x - 1). The square root function is defined only for non-negative values. For x in the interval (0, 1), x - 1 is negative, making the function undefined on this interval. Therefore, it is not continuous on (0, 1).
Step 5: Analyze the function f(x) = x^2. The function x^2 is a polynomial, and polynomials are continuous everywhere. Since the interval (0, 1) is within the domain of x^2, this function is continuous on (0, 1).