Suppose a contour map is given for a function , and you are asked to estimate the partial derivatives and at the point . Which of the following best describes how you would use the contour map to estimate these partial derivatives?
Table of contents
- 0. Functions7h 55m
- Introduction to Functions18m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms36m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 31m
- 12. Techniques of Integration7h 41m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
1. Limits and Continuity
Introduction to Limits
Multiple Choice
Which of the following is true about the graph of in the interval ?
A
The function is increasing throughout the interval .
B
The function has a vertical asymptote at in .
C
The function is continuous and defined for all in .
D
The function is not defined for any in .
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Verified step by step guidance1
Step 1: Begin by analyzing the function y = ln|x^2 - 1|. The natural logarithm function ln(u) is only defined for u > 0. Therefore, we need to determine where the expression |x^2 - 1| is positive.
Step 2: Evaluate the expression x^2 - 1. Factorize it as (x - 1)(x + 1). This shows that x^2 - 1 changes sign at x = -1 and x = 1.
Step 3: Consider the interval (-1, 1). Within this interval, x^2 - 1 is negative because both factors (x - 1) and (x + 1) are negative for x in (-1, 1). Thus, |x^2 - 1| = -(x^2 - 1), which is still negative.
Step 4: Since |x^2 - 1| is negative throughout the interval (-1, 1), the argument of the natural logarithm function ln|x^2 - 1| is not valid (ln is undefined for non-positive values).
Step 5: Conclude that the function y = ln|x^2 - 1| is not defined for any x in the interval (-1, 1). This is the correct answer.
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