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Multiple Choice
Evaluate the indefinite integral as an infinite series: .
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Verified step by step guidance
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Step 1: Begin by expressing the integrand (cos(x) - 1)/x in terms of a series expansion. Recall that the Taylor series expansion for cos(x) is given by: cos(x) = sum_{n=0}^{∞} (-1)^n x^(2n) / (2n)!.
Step 2: Subtract 1 from the Taylor series expansion of cos(x). This modifies the series to: cos(x) - 1 = sum_{n=1}^{∞} (-1)^n x^(2n) / (2n)!.
Step 3: Divide the resulting series (cos(x) - 1) by x. This gives: (cos(x) - 1)/x = sum_{n=1}^{∞} (-1)^n x^(2n-1) / (2n)!.
Step 4: Integrate term by term. The indefinite integral of x^(2n-1) is x^(2n)/(2n). Thus, the integral becomes: int (cos(x) - 1)/x dx = sum_{n=1}^{∞} (-1)^n x^(2n) / [2n (2n)!] + C.
Step 5: Verify the result matches the given correct answer. The final series representation of the integral is: sum_{n=1}^{∞} (-1)^n x^(2n) / [2n (2n)!] + C.