Let be a twice-differentiable function such that , , and . What is the value of the second-degree Taylor polynomial of centered at evaluated at ?
Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 34m
- 12. Techniques of Integration7h 39m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
2. Intro to Derivatives
Differentiability
Struggling with Calculus?
Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Given the system of differential equations: , , , which of the following is the general solution for ?
A
B
C
D

1
Step 1: Analyze the given system of differential equations: dx/dt = z, dy/dt = x, dz/dt = y. Notice that the equations are interdependent, forming a cyclic relationship between x, y, and z.
Step 2: Differentiate dx/dt = z with respect to t to obtain d²x/dt² = dz/dt. Substitute dz/dt = y from the given system into this equation, resulting in d²x/dt² = y.
Step 3: Differentiate d²x/dt² = y with respect to t to obtain d³x/dt³ = dy/dt. Substitute dy/dt = x from the given system into this equation, resulting in d³x/dt³ = x.
Step 4: Recognize that d³x/dt³ = x is a third-order linear differential equation. Its characteristic equation is r³ - 1 = 0, which factors into (r - 1)(r² + r + 1) = 0. Solve for the roots: r = 1 and r = (-1 ± i√3)/2.
Step 5: Use the roots of the characteristic equation to construct the general solution for x(t). The real root r = 1 contributes a term involving e^t, while the complex roots contribute terms involving cos(t), sin(t), and cosh(t). The general solution is x(t) = A cos(t) + B sin(t) + C cosh(t).
Watch next
Master Determining Differentiability Graphically with a bite sized video explanation from Patrick
Start learningRelated Videos
Related Practice
Multiple Choice
23
views
Differentiability practice set
