Let be a differentiable function such that and . What is the value of the derivative of at ?
Table of contents
- 0. Functions7h 55m
- Introduction to Functions18m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms36m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 31m
- 12. Techniques of Integration7h 41m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
2. Intro to Derivatives
Differentiability
Multiple Choice
Which of the following functions is a solution to the differential equation ?
A
B
C
D
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Verified step by step guidance1
Step 1: Understand the problem. The differential equation given is y'' - 4y = 0, where y'' represents the second derivative of y with respect to x. We need to determine which of the provided functions satisfies this equation.
Step 2: Recall the process for verifying solutions to differential equations. To check if a function is a solution, compute its derivatives (up to the second derivative in this case) and substitute them into the differential equation. If the equation holds true, the function is a solution.
Step 3: Start with the first option, y = e^{2x}. Compute the first derivative, y' = 2e^{2x}, and the second derivative, y'' = 4e^{2x}. Substitute these into the equation y'' - 4y = 0: (4e^{2x} - 4e^{2x} = 0). This satisfies the equation, so y = e^{2x} is a solution.
Step 4: Test the second option, y = an(2x). Compute its derivatives and substitute them into the equation. If the equation does not hold, this function is not a solution.
Step 5: Repeat the process for the remaining options, y = x^2 and y = 1/x. Compute their derivatives, substitute them into the equation, and verify whether they satisfy y'' - 4y = 0. Only the function y = e^{2x} will satisfy the equation.
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