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Multiple Choice
Given the parametric equations , for , what is the area enclosed by the curve and the y-axis?
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Verified step by step guidance
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Step 1: Recall the formula for the area enclosed by a parametric curve and the y-axis. The area is given by \( A = \int y \frac{dx}{dt} dt \), where \( y \) and \( x \) are functions of \( t \).
Step 2: Differentiate \( x = \sin^2(t) \) with respect to \( t \) to find \( \frac{dx}{dt} \). Using the chain rule, \( \frac{dx}{dt} = 2\sin(t)\cos(t) \).
Step 3: Substitute \( y = 8\cos(t) \) and \( \frac{dx}{dt} = 2\sin(t)\cos(t) \) into the area formula. The integral becomes \( A = \int_{0}^{\pi} 8\cos(t) \cdot 2\sin(t)\cos(t) dt \).
Step 4: Simplify the integrand. Combine terms to get \( A = \int_{0}^{\pi} 16\sin(t)\cos^2(t) dt \).
Step 5: Use a trigonometric identity to simplify further. Recall \( \cos^2(t) = \frac{1 + \cos(2t)}{2} \). Substitute this into the integral and proceed to evaluate the integral over the given limits \( 0 \leq t \leq \pi \).