Solve the initial value problems in Exercises 53–56 for y as a function of x.
(x² + 1)² (dy/dx) = √(x² + 1), where y(0) = 1
v(t)=−20t+10
v(t)=−20t+5
v(t)=−20t+45
v(t)=−20t−35
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