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Multiple Choice
Solve the following initial value problem: dxdy=2x−5; y(0)=4
A
y(x)=2x2−5x
B
y(x)=x2−5x
C
y(x)=2x2−5x+4
D
y(x)=x2−5x+4
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Verified step by step guidance
1
Start by identifying the given differential equation: \( \frac{dy}{dx} = 2x - 5 \). This is a first-order differential equation.
To solve this differential equation, integrate both sides with respect to \( x \). The left side becomes \( y \) and the right side requires integration: \( \int (2x - 5) \, dx \).
Perform the integration: \( \int 2x \, dx = x^2 \) and \( \int -5 \, dx = -5x \). Combine these results to get \( y = x^2 - 5x + C \), where \( C \) is the constant of integration.
Use the initial condition \( y(0) = 4 \) to find the value of \( C \). Substitute \( x = 0 \) and \( y = 4 \) into the equation: \( 4 = 0^2 - 5(0) + C \), which simplifies to \( C = 4 \).
Substitute \( C = 4 \) back into the equation to get the particular solution: \( y(x) = x^2 - 5x + 4 \).