Solve the initial value problems in Exercises 53–56 for y as a function of x.
√(x² - 9) (dy/dx) = 1, where x > 3, y(5) = ln 3
y(x)=2x2−5x
y(x)=x2−5x
y(x)=2x2−5x+4
y(x)=x2−5x+4
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