Which of the following gives the equations of both lines through the point that are tangent to the parabola ?
Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 34m
- 12. Techniques of Integration7h 39m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
4. Applications of Derivatives
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A 15-foot plank leans against a vertical pole. The top of the plank begins to slide down the pole at a steady speed of 2 inches per second. How fast is the bottom of the plank moving away from the pole when it is 8 feet away from the base of the pole (in inches per second)?
A
dx/dt=1.58sin
B
dx/dt=3.46sin
C
dx/dt=5.04sin
D
dx/dt=3.17sin

1
First, identify the relationship between the variables. The plank, pole, and ground form a right triangle. Let x be the distance from the base of the pole to the bottom of the plank, and y be the height of the top of the plank on the pole. The length of the plank is the hypotenuse, which is 15 feet.
Use the Pythagorean theorem to relate x and y: x^2 + y^2 = 15^2. This equation will help us find the rate at which x changes with respect to time.
Differentiate both sides of the equation with respect to time t to find the relationship between dx/dt and dy/dt. This gives us: 2x(dx/dt) + 2y(dy/dt) = 0.
Substitute the known values into the differentiated equation. We know dy/dt = -2 inches/second (since the top of the plank is sliding down), and we need to find dx/dt when x = 8 feet (convert to inches: 8 feet = 96 inches).
Solve for dx/dt using the equation: 2(96)(dx/dt) + 2(y)(-2) = 0. First, find y when x = 96 inches using the Pythagorean theorem: y^2 = 15^2 - 96^2. Then, substitute y and solve for dx/dt.
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