The perimeter of a rectangle is fixed at . If the length is increasing at a rate of , for what value of does the area start to decrease? Hint: the rectangle's area starts to decrease when the rate of change for the area is less than 0.
Table of contents
- 0. Functions7h 55m
- Introduction to Functions18m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms36m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 31m
- 12. Techniques of Integration7h 41m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
4. Applications of Derivatives
Related Rates
Multiple Choice
Given the equation below, find when and .
A
6
B
1.5
C
36
D
3
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Verified step by step guidance1
First, identify the function y in terms of x. The given function is y = \(\sqrt{2x + 1}\).
To find dy/dt, use the chain rule. The chain rule states that dy/dt = (dy/dx) * (dx/dt).
Calculate dy/dx by differentiating y = \(\sqrt{2x + 1}\) with respect to x. The derivative of \(\sqrt{u}\) with respect to u is (1/2) * u^(-1/2), so dy/dx = (1/2) * (2x + 1)^(-1/2) * 2.
Simplify dy/dx: dy/dx = (1/\(\sqrt{2x + 1}\)).
Substitute x = \(\frac{15}{2}\) and dx/dt = 12 into the expression for dy/dt: dy/dt = (1/\(\sqrt{2(\frac{15}{2}\)) + 1}) * 12.
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