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Multiple Choice
Find the derivative of the given function. f(x)=(x3+4x)sin−1x
A
1−x2x3+4x+(3x2+4)sin−1x
B
1−x23x2+4
C
(3x2+4)sin−1x+(x3+4x)cos−1x
D
(3x2+4)sin−1x−(x3+4x)cos−1x
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1
Identify the function f(x) = (x^3 + 4x) \(\sin\)^{-1}x. This is a product of two functions: u(x) = x^3 + 4x and v(x) = \(\sin\)^{-1}x.
Apply the product rule for differentiation, which states that if you have a function f(x) = u(x)v(x), then its derivative f'(x) = u'(x)v(x) + u(x)v'(x).
Differentiate u(x) = x^3 + 4x. The derivative u'(x) is found by applying the power rule: u'(x) = 3x^2 + 4.
Differentiate v(x) = \(\sin\)^{-1}x. The derivative v'(x) is \(\frac{1}{\sqrt{1-x^2}\)}, which is the standard derivative of the inverse sine function.
Substitute u'(x), v(x), u(x), and v'(x) into the product rule formula: f'(x) = (3x^2 + 4)\(\sin\)^{-1}x + (x^3 + 4x)\(\frac{1}{\sqrt{1-x^2}\)}.