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Multiple Choice
Find the derivative of the given function. f(x)=tan−1(x2)
A
1+x42x
B
1+x22x
C
1+x41
D
sec2(x2)
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Verified step by step guidance
1
Identify the function: We have f(x) = \( \tan^{-1}(x^2) \). This is an inverse tangent function, which requires the use of the chain rule for differentiation.
Recall the derivative of \( \tan^{-1}(u) \): The derivative of \( \tan^{-1}(u) \) with respect to u is \( \frac{1}{1+u^2} \).
Apply the chain rule: Since we have \( u = x^2 \), we need to differentiate \( u \) with respect to x, which gives \( \frac{du}{dx} = 2x \).
Combine the derivatives: Using the chain rule, the derivative of \( f(x) = \tan^{-1}(x^2) \) is \( \frac{d}{dx}[\tan^{-1}(x^2)] = \frac{1}{1+(x^2)^2} \cdot 2x \).
Simplify the expression: The derivative becomes \( \frac{2x}{1+x^4} \) after simplifying \( 1+(x^2)^2 \) to \( 1+x^4 \).