Find the shaded area between & .
Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 34m
- 12. Techniques of Integration7h 39m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
9. Graphical Applications of Integrals
Area Between Curves
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Given the curves and , find the area of the region bounded by these curves between and .
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Step 1: Understand the problem. You are tasked with finding the area of the region bounded by the curves y = x^2 and y = 4 between x = -2 and x = 2. This involves calculating the definite integral of the difference between the upper curve (y = 4) and the lower curve (y = x^2) over the given interval.
Step 2: Set up the integral. The area between two curves is given by the formula: \( \text{Area} = \int_{a}^{b} \left[ f(x) - g(x) \right] dx \), where \( f(x) \) is the upper curve and \( g(x) \) is the lower curve. Here, \( f(x) = 4 \) and \( g(x) = x^2 \), and the interval is \( x \in [-2, 2] \).
Step 3: Write the integral expression. Substitute the functions and interval into the formula: \( \text{Area} = \int_{-2}^{2} \left[ 4 - x^2 \right] dx \). This represents the total area between the curves.
Step 4: Break down the integral. Split the integral into two parts for easier computation: \( \int_{-2}^{2} 4 dx \) and \( \int_{-2}^{2} -x^2 dx \). These can be computed separately and then combined.
Step 5: Apply symmetry. Notice that the function \( -x^2 \) is symmetric about the y-axis, meaning \( \int_{-2}^{2} -x^2 dx = 2 \int_{0}^{2} -x^2 dx \). Similarly, \( \int_{-2}^{2} 4 dx = 2 \int_{0}^{2} 4 dx \). Use this property to simplify the calculations.
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