Given the region bounded above by and below by on the interval , determine the - and -coordinates of the centroid of the shaded area.
Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 34m
- 12. Techniques of Integration7h 39m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
9. Graphical Applications of Integrals
Area Between Curves
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Find the area of the region that lies inside both curves: and .
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Step 1: Understand the problem. The goal is to find the area of the region that lies inside both polar curves: r = sin(2θ) and r = cos(2θ). This involves determining the points of intersection and setting up the integral for the area calculation.
Step 2: Find the points of intersection between the two curves. To do this, set r = sin(2θ) equal to r = cos(2θ). Solve the equation sin(2θ) = cos(2θ) to find the values of θ where the curves intersect. Recall that sin(2θ) = cos(2θ) implies tan(2θ) = 1, so solve for θ.
Step 3: Determine the limits of integration. The points of intersection found in Step 2 will serve as the bounds for the integral. Since the curves are symmetric, you can focus on one region and multiply the result by the appropriate factor to account for symmetry.
Step 4: Set up the integral for the area. The formula for the area enclosed by a polar curve is A = (1/2) ∫ r² dθ. For the region inside both curves, you will need to subtract the area of one curve from the other within the limits of integration. Specifically, the integral will be A = (1/2) ∫ [cos²(2θ) - sin²(2θ)] dθ.
Step 5: Simplify the integrand using trigonometric identities. Use the identity cos²(x) - sin²(x) = cos(2x) to rewrite the integrand. Then, evaluate the integral within the limits of integration determined in Step 3. Multiply the result by any necessary symmetry factor to obtain the total area.
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