Which of the following integrals correctly represents the area of the region enclosed by the curves and for ?
Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
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- 1. Limits and Continuity2h 2m
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- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
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9. Graphical Applications of Integrals
Area Between Curves
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Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
What is the area of the region enclosed by the curves and for ?
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Step 1: Begin by identifying the curves y = sec^2(x) and y = 8 cos(x). The area between these curves is determined by integrating the difference between the two functions over the interval [-π/3, π/3].
Step 2: Set up the integral for the area. Since the correct order of subtraction is y = 8 cos(x) - y = sec^2(x), the integral becomes: ∫_{-π/3}^{π/3} [8 cos(x) - sec^2(x)] dx.
Step 3: Break the integral into two separate integrals for easier computation: ∫_{-π/3}^{π/3} 8 cos(x) dx - ∫_{-π/3}^{π/3} sec^2(x) dx.
Step 4: Evaluate each integral separately. For ∫_{-π/3}^{π/3} 8 cos(x) dx, recall that the integral of cos(x) is sin(x). For ∫_{-π/3}^{π/3} sec^2(x) dx, recall that the integral of sec^2(x) is tan(x).
Step 5: Substitute the limits of integration (-π/3 and π/3) into the results of each integral. Combine the results to find the total area enclosed by the curves.
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