Find the area of the region enclosed by the inner loop of the curve .
Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 34m
- 12. Techniques of Integration7h 39m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
9. Graphical Applications of Integrals
Area Between Curves
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Find the area of the region R bounded by the graphs of , , and .
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Step 1: Identify the region R bounded by the given curves. The curves are y = x^2 + 1 (a parabola), y = 2x (a straight line), and x = 0 (the y-axis). Sketch the graphs to visualize the region of interest.
Step 2: Determine the points of intersection between the curves y = x^2 + 1 and y = 2x. Set x^2 + 1 = 2x and solve for x. Rearrange the equation to x^2 - 2x + 1 = 0, which factors as (x - 1)^2 = 0, giving x = 1.
Step 3: Note that the region is bounded by x = 0 and x = 1. To find the area, set up the integral of the difference between the upper curve (y = 2x) and the lower curve (y = x^2 + 1) over the interval [0, 1]. The area is given by: β«[0 to 1] [(2x) - (x^2 + 1)] dx.
Step 4: Simplify the integrand: (2x) - (x^2 + 1) = -x^2 + 2x - 1. The integral becomes β«[0 to 1] (-x^2 + 2x - 1) dx.
Step 5: Compute the integral term by term: β«[0 to 1] (-x^2) dx + β«[0 to 1] (2x) dx + β«[0 to 1] (-1) dx. Evaluate each term using the power rule for integration and the limits of integration [0, 1]. Combine the results to find the total area.
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