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Multiple Choice
Let be the vector-valued function defined by . Evaluate the definite integral from to of .
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Verified step by step guidance
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Step 1: Understand the problem. You are tasked with evaluating the definite integral of the vector-valued function r(t) = (3t, 1/(t+1), e^{-t}) from t = 0 to t = 1. This involves integrating each component of the vector function separately over the given interval.
Step 2: Break down the vector-valued function into its components: r(t) = (3t, 1/(t+1), e^{-t}). The first component is 3t, the second component is 1/(t+1), and the third component is e^{-t}. Each of these will be integrated individually.
Step 3: Set up the definite integrals for each component:
For the first component: \( \int_{0}^{1} 3t \, dt \)
For the second component: \( \int_{0}^{1} \frac{1}{t+1} \, dt \)
For the third component: \( \int_{0}^{1} e^{-t} \, dt \).
Step 4: Solve each integral step by step:
- For \( \int_{0}^{1} 3t \, dt \), use the power rule for integration: \( \int t^n \, dt = \frac{t^{n+1}}{n+1} \).
- For \( \int_{0}^{1} \frac{1}{t+1} \, dt \), recognize this as the natural logarithm function: \( \int \frac{1}{x} \, dx = \ln|x| \).
- For \( \int_{0}^{1} e^{-t} \, dt \), use the exponential rule for integration: \( \int e^{ax} \, dx = \frac{1}{a} e^{ax} \).
Step 5: Evaluate each integral over the interval [0, 1]:
- For \( \int_{0}^{1} 3t \, dt \), substitute the limits of integration after applying the power rule.
- For \( \int_{0}^{1} \frac{1}{t+1} \, dt \), substitute the limits of integration into the natural logarithm function.
- For \( \int_{0}^{1} e^{-t} \, dt \), substitute the limits of integration into the exponential function. Combine the results into a vector to represent the final answer.