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Ch. 5 - Integration
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 5, Problem 5.RE.15a

Symmetry properties Suppose βˆ«β‚€β΄ Ζ’(𝓍) d𝓍 = 10 and βˆ«β‚€β΄ g(𝓍) d𝓍 = 20. Furthermore, suppose Ζ’ is an even function and g is an odd function. Evaluate the following integrals.


(a) βˆ«β‚‹β‚„β΄ Ζ’(𝓍) d𝓍

Verified step by step guidance
1
Step 1: Understand the symmetry properties of even and odd functions. An even function satisfies Ζ’(𝓍) = Ζ’(-𝓍), meaning it is symmetric about the y-axis. An odd function satisfies g(𝓍) = -g(-𝓍), meaning it is symmetric about the origin.
Step 2: Recall the property of definite integrals for even functions. If Ζ’(𝓍) is even, then βˆ«β‚‹β‚β‚ Ζ’(𝓍) d𝓍 = 2βˆ«β‚€β‚ Ζ’(𝓍) d𝓍. This property will be used to evaluate βˆ«β‚‹β‚„β΄ Ζ’(𝓍) d𝓍.
Step 3: Substitute the given value of βˆ«β‚€β΄ Ζ’(𝓍) d𝓍 = 10 into the formula for even functions. Using the property, βˆ«β‚‹β‚„β΄ Ζ’(𝓍) d𝓍 = 2βˆ«β‚€β΄ Ζ’(𝓍) d𝓍.
Step 4: Simplify the expression by multiplying the given value of βˆ«β‚€β΄ Ζ’(𝓍) d𝓍 by 2. This will give the result for βˆ«β‚‹β‚„β΄ Ζ’(𝓍) d𝓍.
Step 5: Conclude that the integral βˆ«β‚‹β‚„β΄ Ζ’(𝓍) d𝓍 depends entirely on the symmetry property of the even function and the given value of βˆ«β‚€β΄ Ζ’(𝓍) d𝓍.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Even Functions

An even function is defined by the property that Ζ’(βˆ’x) = Ζ’(x) for all x in its domain. This symmetry about the y-axis implies that the area under the curve from -a to 0 is equal to the area from 0 to a. Therefore, when integrating an even function over a symmetric interval, the integral can be simplified to twice the integral from 0 to a.
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Odd Functions

An odd function satisfies the condition g(βˆ’x) = βˆ’g(x) for all x in its domain. This property indicates that the function is symmetric about the origin, leading to the conclusion that the integral of an odd function over a symmetric interval around zero is zero. Thus, when evaluating the integral of an odd function from -a to a, the contributions from the negative and positive sides cancel each other out.
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Definite Integrals and Symmetry

Definite integrals represent the net area under a curve between two points. When evaluating integrals of even and odd functions over symmetric intervals, the properties of these functions allow for simplifications. For even functions, the integral from -a to a can be expressed as twice the integral from 0 to a, while for odd functions, the integral from -a to a equals zero, highlighting the importance of symmetry in calculus.
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Related Practice
Textbook Question

Evaluating integrals Evaluate the following integrals.


βˆ«β‚€ΒΉ 𝓍 β€’ 2ˣ²⁺¹ d𝓍

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Textbook Question

Area functions and the Fundamental Theorem Consider the function

Ζ’(t) = { t      if  β€•2 β‰€ t < 0

tΒ²/2    if    0 β‰€ t β‰€ 2

and its graph shown below. Let F(𝓍) = βˆ«β‚‹β‚Λ£ Ζ’(t) dt and G(𝓍) = βˆ«β‚‹β‚‚Λ£ Ζ’(t) dt.

(e) Evaluate F ''(―1) and F ''(1). Interpret these values.

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Textbook Question

Symmetry properties Suppose βˆ«β‚€β΄ Ζ’(𝓍) d𝓍 = 10 and βˆ«β‚€β΄ g(𝓍) d𝓍 = 20. Furthermore, suppose Ζ’ is an even function and g is an odd function. Evaluate the following integrals.


(e) βˆ«β‚‹β‚‚Β² 3𝓍ƒ(𝓍)d𝓍

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Textbook Question

Explain why or why not Determine whether the following statements are true and give an explanation or counterexample.

(a) Consider the linear function Ζ’(𝓍) = 2x + 5 and the region bounded by its graph and the x-axis on the interval [3,6]. Suppose the area of this region is approximated using midpoint Riemann sums. Then the approximations give the exact area of the region for any number of subintervals.

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Textbook Question

Working with area functions Consider the function Ζ’ and the points a, b, and c.

(a) Find the area function A (𝓍) = βˆ«β‚Λ£ Ζ’(t) dt using the Fundamental Theorem.

Ζ’(𝓍) = sin 𝓍 ; a = 0 , b = Ο€/2 , c = Ο€

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Textbook Question

Symmetry properties Suppose βˆ«β‚€β΄ Ζ’(𝓍) d𝓍 = 10 and βˆ«β‚€β΄ g(𝓍) d𝓍 = 20. Furthermore, suppose Ζ’ is an even function and g is an odd function. Evaluate the following integrals.


(c) βˆ«β‚‹β‚„β΄ (4Ζ’(𝓍) ― 3g(𝓍))d𝓍

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