Let . What is the average value of on the interval ?
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8. Definite Integrals
Average Value of a Function
Multiple Choice
Find the average value of the function on the interval .
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Verified step by step guidance1
Step 1: Recall the formula for the average value of a function f(x) on the interval [a, b]: f_{ave} = (1 / (b - a)) * ∫[a to b] f(x) dx. Here, a = -1 and b = 5.
Step 2: Set up the integral ∫[a to b] f(x) dx for the given function f(x) = 3x^2 + 8x. This becomes ∫[-1 to 5] (3x^2 + 8x) dx.
Step 3: Break the integral into two parts using the linearity of integration: ∫[-1 to 5] (3x^2 + 8x) dx = ∫[-1 to 5] 3x^2 dx + ∫[-1 to 5] 8x dx.
Step 4: Compute the antiderivative of each term. For 3x^2, the antiderivative is (3/3)x^3 = x^3. For 8x, the antiderivative is (8/2)x^2 = 4x^2. Substitute these into the integral.
Step 5: Evaluate the definite integrals by substituting the limits of integration (-1 and 5) into the antiderivatives. Then, divide the result by (b - a) = (5 - (-1)) = 6 to find f_{ave}.
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