Textbook Question
Derivatives of integrals Simplify the following expressions.
d/dt β«βα΅ dπ/(1 + πΒ²) + β«βΒΉ/α΅ dx/(1 + πΒ²)
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8. Definite Integrals
Fundamental Theorem of Calculus
1:42 minutesProblem 5.3.85
Textbook Question
Derivatives of integrals Simplify the following expressions.
d/dπ β«βΛ£ (β1 + tΒ²) dt (Hint: β«Λ£ββ (β1 + tΒ²) dt = β«β°ββ (β1 + tΒ²) dt + β«Λ£ββ (β1 + tΒ²) dt ) .
Verified step by step guidance1
Step 1: Recognize that the problem involves the Fundamental Theorem of Calculus, which states that if F(x) = β«βΛ£ f(t) dt, then dF/dx = f(x). This theorem will be key in solving the derivative of the integral.
Step 2: Analyze the given integral β«βΛ£ (β1 + tΒ²) dt. According to the Fundamental Theorem of Calculus, the derivative of this integral with respect to x is simply the integrand evaluated at the upper limit of integration, which is β(1 + xΒ²).
Step 3: Consider the hint provided: β«Λ£ββ (β1 + tΒ²) dt = β«β°ββ (β1 + tΒ²) dt + β«Λ£ββ (β1 + tΒ²) dt. This suggests breaking the integral into parts, but for the derivative d/dπ β«βΛ£ (β1 + tΒ²) dt, the hint is not directly necessary since the Fundamental Theorem of Calculus simplifies the process.
Step 4: Apply the Fundamental Theorem of Calculus directly to the integral β«βΛ£ (β1 + tΒ²) dt. The derivative with respect to x is simply β(1 + xΒ²), as the lower limit of integration (0) does not contribute to the derivative.
Step 5: Conclude that the derivative of the given integral is β(1 + xΒ²). The hint provided is more relevant for breaking down integrals with different limits, but in this case, the direct application of the theorem suffices.
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1mKey Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Fundamental Theorem of Calculus
The Fundamental Theorem of Calculus links differentiation and integration, stating that if F is an antiderivative of f on an interval [a, b], then the integral of f from a to b can be computed as F(b) - F(a). This theorem also implies that the derivative of an integral function is the integrand evaluated at the upper limit of integration.
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