Calculus
z=2+1055z=2+\(\frac{\sqrt{105}\)}{5}
z=2−1055z=2-\(\frac{\sqrt{105}\)}{5}
z=−2−1055z=-2-\(\frac{\sqrt{105}\)}{5}
z=−2+1055z=-2+\(\frac{\sqrt{105}\)}{5}