determine-the-derivative-of-gx4x43x32x2x4gleftxrightfrac4x43x3-2x2x4

Question

Determine the derivative of g(x)=4x4+3x3−2x2x4g\left(x\right)=\frac{$$4x^4+3x^3$-2x^2$$}{$$x^4$$}.

Accepted Answer

g′(x)=−$$3x2+4x3g^{\prime}$$\left(x\right)=-\frac{3}{$$x^2$$}+\frac{4}{$$x^3$$}

Answer

g′(x)=3x2−$$4x3g^{\prime}$$\left(x\right)=$$3x^2$-4x^3$$

Answer

g′(x)=−$$3x2+4x3g^{\prime}$$\left(x\right)=$$-3x^2$+4x^3$$

Answer

g′(x)=3x2−$$4x3g^{\prime}$$\left(x\right)=\frac{3}{$$x^2$$}-\frac{4}{$$x^3$$}

Determine the derivative of g(x)=4x4+3x3−2x2x4g\(\left\)(x\(\right\))=\(\frac{4x^4+3x^3-2x^2}{x^4}\).