on-the-interval-23leftlbrack-23rightrbrack-find-the-absolute-maximum-and-minimum

Question

On the interval [−2,3]\left\lbrack-2,3\right\rbrack, find the absolute maximum and minimum of the function f(x)=2x5−20x3+50xf\left(x\right)=$$2x^5$-20x^3+50x.$$

Accepted Answer

fmin⁡(−1)=−32f_{\min}\left(-1\right)=-32, fmax⁡(3)=96f_{\max}\left(3\right)=96

Answer

fmin⁡(−2)=−4f_{\min}\left(-2\right)=-4, fmax⁡(3)=96f_{\max}\left(3\right)=96

Answer

fmin⁡(−1)=−32f_{\min}\left(-1\right)=-32, fmax⁡(1)=32f_{\max}\left(1\right)=32

Answer

fmin⁡(−2)=−4f_{\min}\left(-2\right)=-4, fmax⁡(1)=32f_{\max}\left(1\right)=32

On the interval [−2,3]\(\left\[\lbrack\)-2,3\(\right\]\rbrack\), find the absolute maximum and minimum of the function f(x)=2x5−20x3+50xf\(\left\)(x\(\right\))=2x^5-20x^3+50x.

On the interval $open bracket negative 2 comma 3 close bracket$ , find the absolute maximum and minimum of the function $f (x) = 2 x^{5} - 20 x^{3} + 50 x$ .