Calculus
f′(x)=3x2−15x+4(3x2+4)5f^{\(\prime\)}\(\left\)(x\(\right\))=\(\frac{3x^2-15x+4}{\left(3x^2+4\right)^5}\)
f′(x)=4−27x2x(3x2+4)f^{\(\prime\)}\(\left\)(x\(\right\))=\(\frac{4-27x^2}{x\left(3x^2+4\right)}\)
f′(x)=30x2−4x(3x2+4)f^{\(\prime\)}\(\left\)(x\(\right\))=\(\frac{30x^2-4}{x\left(3x^2+4\right)}\)
f′(x)=27x2−4x2(3x2+4)f^{\(\prime\)}\(\left\)(x\(\right\))=\(\frac{27x^2-4}{x^2\left(3x^2+4\right)}\)