A rock is thrown vertically upward from the top of a $250\text{ m}$ cliff with an initial velocity of $15\(\text{ m/s}\)$. Assume only gravity acts on the rock $(g=9.8{\text{ m/s}}^2)$. At what time does the rock reach its maximum height? What is that height?

$t=\frac{49}{75}\text{ s}$

$s=261\frac{98}{47}\text{ m}$

$t=\frac{75}{49}\text{ s}$

$s=261\frac{98}{47}\text{ m}$

$t=\frac{49}{75}\text{ s}$

$s=261\frac{47}{98}\text{ m}$

$t=\frac{75}{49}\text{ s}$

$s=261\frac{47}{98}\text{ m}$