find-a-possible-function-hxhleftxright-and-a-number-cc-such-that-the-following-l

Question

Find a possible function h(x)h\left(xight) and a number cc such that the following limit represents the slope of the curve y=h(x)y=h\left(xight) at (c,h(c))(c,h(c)). Then, evaluate the limit:lim⁡x→−14x2−2x−6x+1{\displaystyle\lim_{x	o-1}}\frac{$$4x^2-2x-6$$}{x+1}

Accepted Answer

h(x)=4x2−2xh\left(xight)=$$4x^2-2xc$$=−1c=-1lim⁡x→−14x2−2x−6x+1{\displaystyle\lim_{x	o-1}}\frac{$$4x^2-2x-6$$}{x+1} == −10-10

Answer

h(x)=4x2−2xh\left(xight)=$$4x^2-2xc$$=−1c=-1lim⁡x→−14x2−2x−6x+1{\displaystyle\lim_{x	o-1}}\frac{$$4x^2-2x-6$$}{x+1} == 1010

Answer

h(x)=4x2+2xh\left(xight)=$$4x^2+2xc$$=−1c=-1lim⁡x→−14x2−2x−6x+1{\displaystyle\lim_{x	o-1}}\frac{$$4x^2-2x-6$$}{x+1} == 1010

Answer

h(x)=4x2+2xh\left(xight)=$$4x^2+2xc=1c=1$$lim⁡x→−14x2−2x−6x+1{\displaystyle\lim_{x	o-1}}\frac{$$4x^2-2x-6$$}{x+1} == −10-10