without-finding-the-derivative-of-ycos1xycos-1x-determine-the-slope-of-the-line-

Question

Without finding the derivative of y=cos⁡−1xy=\$$cos^{-1}x$$, determine the slope of the line tangent to y=cos⁡−1xy=\$$cos^{-1}x at (12$$,π3)\left(\frac12,\frac{\pi}{3}\right).

Accepted Answer

−233-\frac{2\sqrt3}{3}

Answer

−23-2\sqrt3

Answer

2\sqrt2

Answer

−22-\frac{\sqrt2}{2}

Without finding the derivative of y=cos−1xy=\(\cos\)^{-1}x, determine the slope of the line tangent to y=cos−1xy=\(\cos\)^{-1}x at (12,π3)\(\left\)(\(\frac\)12,\(\frac{\pi}{3}\]\right\)).

Without finding the derivative of $y = \cos^{- 1} x$ , determine the slope of the line tangent to $y = \cos^{- 1} x$ at $open paren one half comma pi over 3 close paren$ .