a-wave-travels-along-a-string-and-its-height-in-millimeters-is-described-by-ht15

Question

A wave travels along a string, and its position in millimeters is described by h(t)=15(2cos⁡t+1)h\left(t\right)=15\left(2\cos t+1\right), for t≥0t\geq0, where tt represents time in seconds. Determine the velocity of the wave, v(t)=h′(t)v\left(t\right)=$$h^{\prime}$$\left(t\right).

Accepted Answer

v(t)=−30sin⁡t mm/sv\left(tight)=-30\sin t	ext{ mm/s}

Answer

v(t)=30sin⁡t mm/sv\left(tight)=30\sin t	ext{ mm/s}

Answer

v(t)=15sec⁡2t mm/sv\left(tight)=15\$$sec^2t$$	ext{ mm/s}

Answer

v(t)=−30csc⁡2t mm/sv\left(tight)=-30\$$csc^2t$$	ext{ mm/s}