Calculus
dy=−2bsin(2x)dxdy=-2b\(\sin\]\left\)(2x\(\right\))dx
dy=2bsin(2x)dxdy=2b\(\sin\]\left\)(2x\(\right\))dx
dy=bsin(2x)dxdy=b\(\sin\]\left\)(2x\(\right\))dx
dy=−bsin(2x)dxdy=-b\(\sin\]\left\)(2x\(\right\))dx