use-the-following-theorem-to-evaluate-limx0tan14xxdisplaystyle-limx-to-0fractan1

Question

Use the following theorem to evaluate lim⁡x→0tan⁡14xx\displaystyle \lim_{x 	o 0}{\frac{	an{14x}}{x}}:lim⁡x→0sin⁡xx=1\displaystyle \lim_{x 	o 0}{\frac{\sin{x}}{x}}=1

Accepted Answer

1414

Answer

−7-7

Answer

00

Answer

2828

Use the following theorem to evaluate limx→0tan14xx\(\displaystyle\) \(\lim\)_{x \(\to\) 0}{\(\frac{\tan{14x}\)}{x}}:limx→0sinxx=1\(\displaystyle\) \(\lim\)_{x \(\to\) 0}{\(\frac{\sin{x}\)}{x}}=1

Use the following theorem to evaluate $\lim_{x \to 0} \frac{\tan 14 x}{x}$ :
$\lim_{x \to 0} \frac{\sin x}{x} = 1$