Calculus
V′(10)=4V^{\(\prime\)}(10)=4 m3/s\(\text{ m}\)^3\(\text{/s}\)
The rate of change of the volume of the balloon is 4 m3/s4\(\text{ m}\)^3\(\text{/s}\) at t=10t=10 s\(\text{ s}\).
V′(10)=10V^{\(\prime\)}\(\left\)(10\(\right\))=10 m3/s\(\text{ m}\)^3\(\text{/s}\)
The rate of change of the volume of the balloon is 1010 m3/s\(\text{ m}\)^3\(\text{/s}\) at t=10t=10 s\(\text{ s}\).
V′(10)=40V^{\(\prime\)}\(\left\)(10\(\right\))=40 m3/s\(\text{ m}\)^3\(\text{/s}\)
The rate of change of the volume of the balloon is 4040 m3/s\(\text{ m}\)^3\(\text{/s}\) at t=10t=10 s\(\text{ s}\).
V′(10)=5V^{\(\prime\)}\(\left\)(10\(\right\))=5 m3/s\(\text{ m}\)^3\(\text{/s}\)
The rate of change of the volume of the balloon is 55 m3/s\(\text{ m}\)^3\(\text{/s}\) at t=10t=10 s\(\text{ s}\).