a-tangent-line-to-the-curve-of-gg-at-the-point-32left3-2right-is-given-by-the-eq

Question

A tangent line to the curve gg at the point (3,−2)\left(3,-2\right) is given by the equation y=−3x+7y=-3x+7. What are g(3)g\left(3\right) and g′$$(3)g^{\prime}$$\left(3\right)?

Accepted Answer

g(3)=−2g\left(3\right)=-2g′(3)=−$$3g^{\prime}$$\left(3\right)=-3

Answer

g(3)=−2g\left(3\right)=-2g′(3)=$$7g^{\prime}$$\left(3\right)=7

Answer

g(3)=2g\left(3\right)=2g′(3)=−$$3g^{\prime}$$\left(3\right)=-3

Answer

g(3)=−3g\left(3\right)=-3g′(3)=−$$2g^{\prime}$$\left(3\right)=-2

A tangent line to the curve gg at the point (3,−2)\(\left\)(3,-2\(\right\)) is given by the equation y=−3x+7y=-3x+7. What are g(3)g\(\left\)(3\(\right\)) and g′(3)g^{\(\prime\)}\(\left\)(3\(\right\))?

A tangent line to the curve $g$ at the point $open paren 3 comma negative 2 close paren$ is given by the equation $y = - 3 x + 7$ . What are $g of 3$ and $g prime of 3$ ?