use-a-shift-to-explain-how-the-graph-of-hxx26x27hxsqrt-x2-6x27-is-obtained-from-

Question

Use a shift to explain how the graph of h(x)=−x2−6x+27h(x)=\sqrt{$$-x^2-6x+27$$} is obtained from the graph of p(x)=36−x2p(x)=\sqrt{$$36-x^2$$}. Which of the following transformations applies? Draw the graph of h(x).

Accepted Answer

Shift the graph of p(x) to the left side by 3 units.

Answer

Shift the graph of p(x) to the right side by 3 units.

Answer

Stretch the graph of p(x) vertically by a factor of 3.

Answer

Shift the graph of p(x) to the left side by 3 units.

Use a shift to explain how the graph of h(x)=−x2−6x+27h(x)=\(\sqrt{-x^2-6x+27}\) is obtained from the graph of p(x)=36−x2p(x)=\(\sqrt{36-x^2}\). Which of the following transformations applies? Draw the graph of h(x).

Use a shift to explain how the graph of $h (x) = \sqrt{- x^{2} - 6 x + 27}$ is obtained from the graph of $p (x) = \sqrt{36 - x^{2}}$ . Which of the following transformations applies? Draw the graph of h(x).