If x²y³ = 4/27 and dy/dt = ¹/₂, then what is dx/dt when x = 2?
Find the derivatives of the functions in Exercises 1–42.
𝔂 = 2 tan² x - sec² x
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Key Concepts
Derivative
Trigonometric Functions
Chain Rule
For what value of c is the curve y = c/ (x + 1) tangent to the line through the points (0, 3) and (5, -2)?
Finding g on a small airless planet Explorers on a small airless planet used a spring gun to launch a ball bearing vertically upward from the surface at a launch velocity of 15 m/sec. Because the acceleration of gravity at the planet’s surface was gₛ m/sec², the explorers expected the ball bearing to reach a height of s = 15t − (1/2)gₛt² m t sec later. The ball bearing reached its maximum height 20 sec after being launched. What was the value of gₛ?
Derivatives in Differential Form
In Exercises 17–28, find dy.
y = cos(x²)
Approximation Error
In Exercises 29–34, each function f(x) changes value when x changes from x₀ to x₀ + dx. Find
a. the change Δf = f(x₀ + dx) − f(x₀);
b. the value of the estimate df = fʹ(x₀) dx; and
c. the approximation error |Δf − df|.
f(x) = x⁴, x₀ = 1, dx = 0.1
In Exercises 41–58, find dy/dt.
y = (1/6)(1 + cos²(7t))³
