Textbook Question
Theory and Examples
Determine the values of constants a and b so that f(x) = ax² + bx has an absolute maximum at the point (1,2).
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Ch. 4 - Applications of Derivatives
Hass15th EditionThomas' CalculusISBN: 9780137616077
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Table of contents
- Ch. 1 - Functions155
- Ch. 2 - Limits and Continuity240
- Ch. 3 - Derivatives337
- Ch. 4 - Applications of Derivatives293
- Ch. 5 - Integrals41
- Ch. 6 - Applications of Definite Integrals25
- Ch. 7 - Transcendental Functions489
- Ch. 8 - Techniques of Integration398
- Ch. 9 - First-Order Differential Equations60
- Ch. 10 - Infinite Sequences and Series119
- Ch. 11 - Parametric Equations and Polar Coordinates58
Chapter 4, Problem 4.5.67
Theory and Examples
67. An inequality for positive integers Show that if a, b, c, and d are positive integers, then
[(a^2+1)(b^2+1)(c^2+1)(d^2+1)]/abcd ≥ 16
Verified step by step guidance1
Recognize that the problem involves proving an inequality for positive integers a, b, c, and d. The expression to analyze is \( \frac{(a^2+1)(b^2+1)(c^2+1)(d^2+1)}{abcd} \geq 16 \).
Apply the AM-GM inequality, which states that for any non-negative numbers, the arithmetic mean is greater than or equal to the geometric mean. For two numbers x and y, this is \( \frac{x + y}{2} \geq \sqrt{xy} \).
Consider each term \( a^2 + 1 \), \( b^2 + 1 \), \( c^2 + 1 \), and \( d^2 + 1 \) separately. Apply the AM-GM inequality to each: \( a^2 + 1 \geq 2a \), \( b^2 + 1 \geq 2b \), \( c^2 + 1 \geq 2c \), and \( d^2 + 1 \geq 2d \).
Multiply the inequalities obtained from the AM-GM application: \( (a^2 + 1)(b^2 + 1)(c^2 + 1)(d^2 + 1) \geq (2a)(2b)(2c)(2d) = 16abcd \).
Divide both sides of the inequality by \( abcd \) to obtain \( \frac{(a^2+1)(b^2+1)(c^2+1)(d^2+1)}{abcd} \geq 16 \), thus proving the original inequality.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Inequality
An inequality is a mathematical statement that compares two values, expressions, or quantities, indicating that one is larger or smaller than the other. In this problem, the inequality involves positive integers and requires proving that a certain expression is greater than or equal to 16. Understanding inequalities is crucial for manipulating and comparing expressions to establish the required relationship.
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AM-GM Inequality
The Arithmetic Mean-Geometric Mean (AM-GM) Inequality is a fundamental inequality in mathematics that states for any non-negative real numbers, the arithmetic mean is greater than or equal to the geometric mean. This concept is often used to prove inequalities involving products and sums, and it can be applied here to show that the expression involving a, b, c, and d meets the required condition.
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Positive Integers
Positive integers are the set of all whole numbers greater than zero. In this problem, a, b, c, and d are specified as positive integers, which means they are natural numbers. This restriction is important because it influences the properties of the expressions involved, such as ensuring that the product abcd is non-zero, allowing for division and comparison in the inequality.
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Related Practice
Textbook Question
30. Find a positive number for which the sum of its reciprocal and four times its square is the smallest possible.
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Textbook Question
Finding Functions from Derivatives
Suppose that f(0) = 5 and that f'(x) = 2 for all x. Must f(x) = 2x + 5 for all x? Give reasons for your answer.
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Textbook Question
93. The accompanying figure shows a portion of the graph of a twice-differentiable function y=f(x). At each of the five labeled points, classify y' and \(\y\)'' as positive, negative, or zero.
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Textbook Question
32. Answer Exercise 31 if one piece is bent into a square and the other into a circle.
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