Textbook QuestionIn Exercises 1–14, simplify the expression or solve the equation, whichever is appropriate.3(2x-5)-2(4x+1)=-5(x+3)-2517views
Textbook QuestionIn Exercises 1–34, solve each rational equation. If an equation has no solution, so state.8/x²−9 + 4/x+3 = 2/x−3611views
Textbook QuestionIn Exercises 1–26, solve and check each linear equation.2(x - 1) + 3 = x - 3(x + 1)680views
Textbook QuestionIn Exercises 1–26, solve and check each linear equation.25 - [2 + 5y - 3(y + 2)] = - 3(2y - 5) - [5(y - 1) - 3y + 3]615views1rank
Textbook QuestionIn Exercises 15–35, solve each equation. Then state whether the equation is an identity, a conditional equation, or an inconsistent equation. 2x/3 = 6 - x/4618views
Textbook QuestionExercises 27–40 contain linear equations with constants in denominators. Solve each equation.20 - x/3 = x/2618views
Textbook QuestionIn Exercises 1–34, solve each rational equation. If an equation has no solution, so state.4/(x²+3x−10) + 1/(x²+9x+20) = 2/(x²+2x−8)518views
Textbook QuestionExercises 27–40 contain linear equations with constants in denominators. Solve each equation.3x/5 - x = x/10 - 5/2522views
Textbook QuestionDetermine whether each equation is an identity, a conditional equation, or a contradic-tion. Give the solution set. -6(2x+1) - 3(x-4) = -15x+1642views
Textbook QuestionSolve each formula for the specified variable. Assume that the denominator is not 0 if variables appear in the denominator. I=Prt,for P (simple interest)792views