Textbook Question
If 5 times a number is decreased by 4, the principal square root of this difference is 2 less than the number. Find the number(s).
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If 5 times a number is decreased by 4, the principal square root of this difference is 2 less than the number. Find the number(s).
Solve each equation in Exercises 83–108 by the method of your choice. 1/x + 1/(x + 3) = 1/4
Solve each equation in Exercises 83–108 by the method of your choice. 3/(x - 3) + 5/(x - 4) = (x2 - 20)/(x2 - 7x + 12)
Solve each equation. - 2{7 - [4 -2(1 - x) + 3]} = 10 - [4x - 2(x - 3)]
When 3 times a number is subtracted from 4, the absolute value of the difference is at least 5. Use interval notation to express the set of all numbers that satisfy this condition.
Solve each equation in Exercises 83–108 by the method of your choice. 2x/(x - 3) + 6/(x + 3) = - 28/(x2 - 9)