Multiple Choice
How many milliliters of a 0.250 M sucrose solution are required to prepare 400.0 mL of a 0.0310 M sucrose solution?
71
views
6. Chemical Quantities & Aqueous Reactions
Dilutions
Multiple Choice
What volume of a 0.100 M HCl stock solution is required to prepare 250.00 mL of 0.0250 M HCl?
A
62.5 mL
B
125.0 mL
C
25.0 mL
D
100.0 mL
Verified step by step guidance1
Identify the known values: the concentration of the stock solution \(C_1 = 0.100\ \text{M}\), the desired concentration of the diluted solution \(C_2 = 0.0250\ \text{M}\), and the volume of the diluted solution \(V_2 = 250.00\ \text{mL}\).
Recall the dilution equation which relates the concentrations and volumes before and after dilution: \(C_1 \times V_1 = C_2 \times V_2\), where \(V_1\) is the volume of the stock solution needed.
Rearrange the dilution equation to solve for \(V_1\): \(V_1 = \frac{C_2 \times V_2}{C_1}\).
Substitute the known values into the equation: \(V_1 = \frac{0.0250\ \text{M} \times 250.00\ \text{mL}}{0.100\ \text{M}}\).
Calculate \(V_1\) to find the volume of the 0.100 M HCl stock solution required to prepare 250.00 mL of 0.0250 M HCl.
Related Videos
Related Practice
