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Multiple Choice
How many milliliters of a 2.00 M NaCl stock solution are required to prepare 100.0 mL of a 0.150 M NaCl solution?
A
15.0 mL
B
75.0 mL
C
30.0 mL
D
7.5 mL
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Verified step by step guidance
1
Identify the known values: the concentration of the stock solution \(C_1 = 2.00\, M\), the desired concentration of the diluted solution \(C_2 = 0.150\, M\), and the final volume of the diluted solution \(V_2 = 100.0\, mL\).
Recall the dilution equation which relates the concentrations and volumes before and after dilution:
\[C_1 \times V_1 = C_2 \times V_2\]
where \(V_1\) is the volume of the stock solution needed.
Rearrange the dilution equation to solve for \(V_1\):
\[V_1 = \frac{C_2 \times V_2}{C_1}\]
Substitute the known values into the equation:
\[V_1 = \frac{0.150\, M \times 100.0\, mL}{2.00\, M}\]
Calculate \(V_1\) to find the volume of the 2.00 M NaCl stock solution required to prepare 100.0 mL of 0.150 M NaCl solution.