Multiple Choice
Which of the following statements correctly describes the Lewis dot structure of the neutral compound H2S2?
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11. Bonding & Molecular Structure
Lewis Dot Structures: Neutral Compounds
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Which of the following statements correctly describes the Lewis dot structure of the neutral compound SeF_4?
A
SeF_4 has a central selenium atom with three single bonds to fluorine atoms and two lone pairs on selenium.
B
SeF_4 has a central selenium atom with four single bonds to fluorine atoms and one lone pair on selenium.
C
SeF_4 has a central selenium atom with four single bonds to fluorine atoms and no lone pairs on selenium.
D
SeF_4 has a central selenium atom with double bonds to each fluorine atom.
Verified step by step guidance1
Step 1: Determine the total number of valence electrons for the molecule SeF_4. Selenium (Se) is in group 16 and has 6 valence electrons, and each fluorine (F) atom is in group 17 with 7 valence electrons. Multiply the number of fluorine atoms by 7 and add to selenium's 6 electrons.
Step 2: Identify the central atom, which is selenium (Se), because it is less electronegative than fluorine and can expand its octet due to being in period 4.
Step 3: Draw single bonds between the central selenium atom and each of the four fluorine atoms. Each single bond accounts for 2 electrons, so subtract these bonding electrons from the total valence electrons.
Step 4: Distribute the remaining electrons as lone pairs to complete the octets of the fluorine atoms first, since fluorine atoms typically have three lone pairs to complete their octet.
Step 5: Assign any leftover electrons to the central selenium atom as lone pairs. Since selenium can have an expanded octet, check if there is one lone pair remaining on selenium after bonding with four fluorines, which matches the correct Lewis structure description.
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