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Multiple Choice
Which of the following statements correctly describes the Lewis dot structure of the neutral compound XeCl_4?
A
XeCl_4 has a central Xe atom with two single bonds to Cl atoms and four lone pairs on Xe.
B
XeCl_4 has a central Xe atom surrounded by four single bonds to Cl atoms and no lone pairs on Xe.
C
XeCl_4 has a central Xe atom surrounded by four single bonds to Cl atoms and two lone pairs on Xe.
D
XeCl_4 has a central Xe atom with four double bonds to Cl atoms and no lone pairs on Xe.
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Verified step by step guidance
1
Step 1: Identify the central atom and the surrounding atoms in XeCl_4. Xenon (Xe) is the central atom, and it is bonded to four chlorine (Cl) atoms.
Step 2: Determine the total number of valence electrons. Xenon has 8 valence electrons, and each chlorine has 7 valence electrons. For XeCl_4, total valence electrons = 8 (Xe) + 4 × 7 (Cl) = 36 electrons.
Step 3: Draw single bonds between the central Xe atom and each of the four Cl atoms. Each single bond accounts for 2 electrons, so 4 bonds use 8 electrons.
Step 4: Distribute the remaining electrons to satisfy the octet rule for the chlorine atoms first. Each Cl needs 6 more electrons (3 lone pairs) to complete its octet, so 4 × 6 = 24 electrons are used here.
Step 5: Assign the leftover electrons to the central Xe atom as lone pairs. After bonding and filling Cl octets, the remaining electrons form two lone pairs on Xe, consistent with the expanded octet possible for xenon.