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Multiple Choice
Which of the following represents the correct electron configuration for the Ba^{2+} ion?
A
[Xe]
B
[Kr] 5s^2 4d^{10}
C
[Ba] 2+
D
[Xe] 6s^2
Verified step by step guidance
1
Step 1: Identify the atomic number of barium (Ba), which is 56, and write its ground-state electron configuration. The full configuration for neutral Ba is $[Xe] 6s^2$, where $[Xe]$ represents the electron configuration of xenon (54 electrons).
Step 2: Understand that the Ba$^{2+}$ ion is formed by removing two electrons from the neutral Ba atom. Since electrons are removed first from the outermost shell, remove the two 6s electrons.
Step 3: After removing the two 6s electrons, the electron configuration of Ba$^{2+}$ becomes the same as that of xenon, which is $[Xe]$.
Step 4: Compare the given options with the expected electron configuration for Ba$^{2+}$. The correct configuration should match $[Xe]$ without the 6s electrons.
Step 5: Conclude that the correct electron configuration for Ba$^{2+}$ is $[Xe]$, as it reflects the removal of the two 6s electrons from neutral barium.