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Multiple Choice
Which of the following represents the correct electron configuration for a neutral atom of titanium (atomic number 22)?
A
1s^2 2s^2 2p^6 3s^2 3p^6 3d^4
B
1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 4d^2
C
1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^2
D
1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^4
Verified step by step guidance
1
Identify the atomic number of titanium, which is 22. This means a neutral titanium atom has 22 electrons to arrange in its electron configuration.
Recall the order in which electron orbitals are filled according to the Aufbau principle: 1s, 2s, 2p, 3s, 3p, 4s, then 3d.
Fill the orbitals in order, making sure to add electrons up to the total of 22: start with 1s^2 (2 electrons), then 2s^2 (2 electrons), 2p^6 (6 electrons), 3s^2 (2 electrons), 3p^6 (6 electrons), 4s^2 (2 electrons), and finally 3d electrons.
Since 1s, 2s, 2p, 3s, and 3p orbitals together hold 18 electrons, the remaining 4 electrons go into the 4s and 3d orbitals. According to the correct filling order, 4s fills before 3d, so 4s gets 2 electrons and 3d gets the remaining 2 electrons.
Write the final electron configuration as $1s^2\ 2s^2\ 2p^6\ 3s^2\ 3p^6\ 4s^2\ 3d^2$, which correctly represents the distribution of 22 electrons in a neutral titanium atom.