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Multiple Choice
Which of the following best describes the molecular polarity of the ion ICl_4^-?
A
ICl_4^- is polar due to its lone pair.
B
ICl_4^- is a nonpolar molecule.
C
ICl_4^- is a polar molecule.
D
ICl_4^- is nonpolar because it has no lone pairs.
Verified step by step guidance
1
Step 1: Determine the Lewis structure of the ion ICl_4^-. Iodine (I) is the central atom bonded to four chlorine (Cl) atoms, and the ion carries a negative charge, indicating extra electrons to consider.
Step 2: Count the total valence electrons. Iodine has 7 valence electrons, each chlorine has 7, and there is 1 extra electron due to the negative charge. Calculate total electrons: 7 (I) + 4 × 7 (Cl) + 1 (charge) = 36 electrons.
Step 3: Arrange the electrons to satisfy the octet rule for each atom. Place bonding pairs between iodine and each chlorine, then distribute remaining electrons as lone pairs, especially on iodine.
Step 4: Determine the molecular geometry using VSEPR theory. With four bonding pairs and two lone pairs on iodine, the electron geometry is octahedral, but the molecular shape is square planar due to the lone pairs being opposite each other.
Step 5: Analyze the polarity. In a square planar shape, the dipole moments of the I–Cl bonds cancel out due to symmetry, and the lone pairs are arranged symmetrically, making the overall molecule nonpolar.